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Of course the cartridge has effective mass. It depends on the position of the pivot and the force applied in conjunction with it's center of mass, if talking about circular movement (our case). On straight movement, it's mass is also the effective. When I said a cart hasn't an effective mass of...

Although I don't understand the question clearly I will try to answer. A specific tonearm has a specific effective mass and this effective mass is determined by the center of mass and it's distance from the pivot. A cartridge does not have a specific effective mass by it's own since it's not...

Merry Christmas!!!

As what I understand (not being an expert) in plain words: High compliance cart means that the stylus is more free to travel up and down due to a softer suspension. So, if this cart is attached on a heavy arm, any warping of the vinyl will make the stylus absorb the most energy since it will be...

See it differently. If a unique formula and unique equation was true, then every respected manufacturer would follow this exact formula. Not only on turntables but on everything that is involved with sound. But sound is perceived differently among people. Maybe that's why there is such a...

To my eyes, predicament no3 is the most important. Indeed, the position of the counterweight affects the effective mass. Plus, one factor that nobody takes it seriously: all these calculations are made with the hypothesis that all bearings have zero (0) resistance...

Is it bad that I prefer Linda Evangelista?

Oh!, yeah!!! And something tells me I'm at the right place... :occasion5:

:D:D:D:D:D:D:D Seriously, I own a true turntable for only a year. So I call myself a rookie. I have yet a lot of things to learn!

Do, please! It would be extremely helpful for a turntables rookie, like me!!!

And we have to estimate the drag of the needle and the downforce the negative vta offers on the diamond tip!

Simplified (very!!!) maths: x = the weight of the tonearm + cart on earth y = the weight of the counterweight on earth z = the vtf We have: x - y = z Now on the moon: x/6 - y/6 = z/6 Obviously, z ≠ z/6 Sorry mates, I have to stop here and quit the game!!!

Yes, on the 1/6 analogy.

I found one simpler example! Put on a double scale two weights: on one side a 6 grams and on the opposite side a 5 grams. Do we agree that the difference is 1 gram? If we glue a needle under the side of which we put the 6 grams, will this needle put on the vinyl this 1 gram difference? Now...

The key phrase here is that the cart/tonearm/counterweight isn't balanced/equilibrium since an amount of force is put on the vinyl. This force is made out of mass. The mass produces force because the earth pulls it with a specific value (g). The moon will pull this exact mass with a specific...

My trying to enlightening... The system "cart - tonearm - pivot point - counterweight" isn't at equilibrium. It balances due to the needle touching the record, transferring the force that is on excess, to the vinyl. So, if you remove the vinyl, our system will continue to tilt until the needle...

I don't disagree, at all with both Borut and Jim. I just see it from a different perspective. To my eyes (and ears and... belly, why not?!!!:D) it seems that chasing perfection in hi-fi reproduction is like hunting witches. Every step on the reproduction path has tolerances and sometimes...

Specs.... Well, it's something very mysterious. To chace that last 0.01db... no, thanks. For me, sounds good? It's good... As one person I really respect (and I think he's here) said once, sound quality can't always pass on the paper. Maths is good, physics is good but likes and taste don't have...

The above post of mine proves how physics has impact on sound reproduction. Even hydrostatic gets involved!!! :D:D:D Truly sorry for the off topic! @borchee mate thanks for the conversation. I don't disagree with you, I just stand on details.

I don't disagree with that! Exactly! The same applies to your example of aluminum and gold. They both have the same gravitational pull. This pull is a force that depends on the mass and the g. Since both bodies locate at the same point and have the same mass then the gravitational pull/force...